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	<title>Comments on: What is the limit as x approaches 3 from the left?</title>
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	<pubDate>Tue, 22 May 2012 11:45:45 +0000</pubDate>
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		<title>By: kro t</title>
		<link>http://cutframetv.com/x/what-is-the-limit-as-x-approaches-3-from-the-left/comment-page-1#comment-10063</link>
		<dc:creator>kro t</dc:creator>
		<pubDate>Tue, 27 Oct 2009 07:31:59 +0000</pubDate>
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		<description>from the left:
that means you plug in values just to the left of 3 on a number line, like 2.999

so (4*2.999 - 12)/(3-2.999) = -4
(4*2.9999 - 12)/(3-2.9999)= -4

so -4

from the right:
so (4*3.001 - 12)/(3-3.001) = -4
(4*3.0001 - 12)/(3-3.0001)= -4

so -4

which we could have determined by factoring the problem

(4x - 12)/(3- x) = -4(3 - x)/(3 - x) = -4!&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>from the left:<br />
that means you plug in values just to the left of 3 on a number line, like 2.999</p>
<p>so (4*2.999 - 12)/(3-2.999) = -4<br />
(4*2.9999 - 12)/(3-2.9999)= -4</p>
<p>so -4</p>
<p>from the right:<br />
so (4*3.001 - 12)/(3-3.001) = -4<br />
(4*3.0001 - 12)/(3-3.0001)= -4</p>
<p>so -4</p>
<p>which we could have determined by factoring the problem</p>
<p>(4x - 12)/(3- x) = -4(3 - x)/(3 - x) = -4!<br /><b>References : </b></p>
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