Comments on: How to determine value of X when adding log with different bases? http://cutframetv.com/x/how-to-determine-value-of-x-when-adding-log-with-different-bases Wed, 23 May 2012 16:25:47 +0000 http://wordpress.org/?v=2.7 hourly 1 By: s k http://cutframetv.com/x/how-to-determine-value-of-x-when-adding-log-with-different-bases/comment-page-1#comment-9804 s k Sat, 17 Oct 2009 02:11:59 +0000 http://cutframetv.com/x/how-to-determine-value-of-x-when-adding-log-with-different-bases#comment-9804 ln(x)/ln(16)+ln(x)/ln(4)+ln(x)/ln(2)=7 ln(x)(1/ln(16)+1/ln(4)+1/ln(2))=7 ln(x)=7/(1/ln(16)+1/ln(4)+1/ln(2)) x=e^(7/(1/ln(16)+1/ln(4)+1/ln(2))) Here, it helps to know that ln(16)=4ln(2) and ln(4)=2ln(2). Remember, ln(a^b)=b*ln(a). x=e^(7/(1/(4ln2)+1/(2ln2)+1/ln2)) x=e^(7/(7/(4ln2))) x=e^(28ln2/7) x=e^(4ln2) x=e^(ln(2^4)) x=e^ln16 x=16<br><b>References : </b><br>BAM. ln(x)/ln(16)+ln(x)/ln(4)+ln(x)/ln(2)=7

ln(x)(1/ln(16)+1/ln(4)+1/ln(2))=7

ln(x)=7/(1/ln(16)+1/ln(4)+1/ln(2))

x=e^(7/(1/ln(16)+1/ln(4)+1/ln(2)))

Here, it helps to know that ln(16)=4ln(2) and ln(4)=2ln(2).
Remember, ln(a^b)=b*ln(a).

x=e^(7/(1/(4ln2)+1/(2ln2)+1/ln2))

x=e^(7/(7/(4ln2)))

x=e^(28ln2/7)

x=e^(4ln2)

x=e^(ln(2^4))

x=e^ln16

x=16
References :
BAM.

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